(3x^2)-73=0

Solution for (3x^2)-73=0 equation:

(3x^2)-73=0

a = 3; b = 0; c = -73;
Δ = b2-4ac
Δ = 02-4·3·(-73)
Δ = 876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{876}=\sqrt{4*219}=\sqrt{4}*\sqrt{219}=2\sqrt{219}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{219}}{2*3}=\frac{0-2\sqrt{219}}{6}
=-\frac{2\sqrt{219}}{6}
=-\frac{\sqrt{219}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{219}}{2*3}=\frac{0+2\sqrt{219}}{6}
=\frac{2\sqrt{219}}{6}
=\frac{\sqrt{219}}{3}
$